h^2+6h=160

Solution for h^2+6h=160 equation:

h^2+6h=160

We move all terms to the left:

h^2+6h-(160)=0

a = 1; b = 6; c = -160;
Δ = b2-4ac
Δ = 62-4·1·(-160)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*1}=\frac{-32}{2}
=-16
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*1}=\frac{20}{2}
=10
$